ILL × OF = IGEEF
What is this puzzle?
Solve the multiplication alphametic puzzle where ILL × OF = IGEEF. Each letter represents a unique digit from 0-9. No number starts with zero.
Difficulty: easy · Category: multiplication · Unique letters: 6
This easy-level multiplication alphametic puzzle features 6 unique letters (E, F, G, I, L, O). In the equation ILL × OF = IGEEF, each letter maps to a distinct digit from 0 to 9. With only 6 of 10 digits used, 4 digits remain unused in the solution. The leading letters I and O cannot represent zero — this is your first constraint. The result "IGEEF" has more digits than any addend, which means there must be a carry into the leftmost position. This is a crucial clue for determining the result's leading letter. As a beginner-friendly puzzle, the constraints are straightforward and the solution can be found through logical deduction without advanced techniques.
- This multiplication alphametic has 6 unique letters to determine.
- Leading letters: I, O. None of these can be zero.
- There are 6 unique letters, so 4 digits from 0–9 will not be used.
- Consider the partial products and how they contribute to each column of the final result.
- With few unique letters, you can often solve this by systematic trial and error.